.Net Tutorial: February 2012

Date and DateTime formats in sqlserver 2008:

The following statements are useful to convert date to different formats like dd/mm/yy,dd:mm:yy:hh:mm:ss and so on…..

SELECT convert(varchar, getdate(), 100) – mon dd yyyy hh:mmAM (or PM)

– Oct 2 2008 11:01AM

SELECT convert(varchar, getdate(), 101) – mm/dd/yyyy -10/02/2008

SELECT convert(varchar, getdate(), 102) – yyyy.mm.dd – 2008.10.02

SELECT convert(varchar, getdate(), 103) – dd/mm/yyyy

SELECT convert(varchar, getdate(), 104) – dd.mm.yyyy

SELECT convert(varchar, getdate(), 105) – dd-mm-yyyy

SELECT convert(varchar, getdate(), 106) – dd mon yyyy

SELECT convert(varchar, getdate(), 107) – mon dd, yyyy

SELECT convert(varchar, getdate(), 108) – hh:mm:ss

SELECT convert(varchar, getdate(), 109) – mon dd yyyy hh:mm:ss:mmmAM (or PM)

– Oct 2 2008 11:02:44:013AM

SELECT convert(varchar, getdate(), 110) – mm-dd-yyyy

SELECT convert(varchar, getdate(), 111) – yyyy/mm/dd

SELECT convert(varchar, getdate(), 112) – yyyymmdd

SELECT convert(varchar, getdate(), 113) – dd mon yyyy hh:mm:ss:mmm

– 02 Oct 2008 11:02:07:577

SELECT convert(varchar, getdate(), 114) – hh:mm:ss:mmm(24h)

SELECT convert(varchar, getdate(), 120) – yyyy-mm-dd hh:mm:ss(24h)

SELECT convert(varchar, getdate(), 121) – yyyy-mm-dd hh:mm:ss.mmm

SELECT convert(varchar, getdate(), 126) – yyyy-mm-ddThh:mm:ss.mmm

– 2008-10-02T10:52:47.513

– SQL create different date styles with t-sql string functions

SELECT replace(convert(varchar, getdate(), 111), ‘/’, ‘ ‘) – yyyy mm dd

SELECT convert(varchar(7), getdate(), 126) – yyyy-mm

SELECT right(convert(varchar, getdate(), 106), 8) – mon yyyy

————

– SQL Server date formatting function – convert datetime to string

————

– SQL datetime functions

– SQL Server date formats

– T-SQL convert dates

– Formatting dates sql server

CREATE FUNCTION dbo.fnFormatDate (@Datetime DATETIME, @FormatMask VARCHAR(32))

RETURNS VARCHAR(32)

BEGIN

DECLARE @StringDate VARCHAR(32)

SET @StringDate = @FormatMask

IF (CHARINDEX (‘YYYY’,@StringDate) > 0)

SET @StringDate = REPLACE(@StringDate, ‘YYYY’,

DATENAME(YY, @Datetime))

IF (CHARINDEX (‘YY’,@StringDate) > 0)

SET @StringDate = REPLACE(@StringDate, ‘YY’,

RIGHT(DATENAME(YY, @Datetime),2))

IF (CHARINDEX (‘Month’,@StringDate) > 0)

SET @StringDate = REPLACE(@StringDate, ‘Month’,

DATENAME(MM, @Datetime))

IF (CHARINDEX (‘MON’,@StringDate COLLATE SQL_Latin1_General_CP1_CS_AS)>0)

SET @StringDate = REPLACE(@StringDate, ‘MON’,

LEFT(UPPER(DATENAME(MM, @Datetime)),3))

IF (CHARINDEX (‘Mon’,@StringDate) > 0)

SET @StringDate = REPLACE(@StringDate, ‘Mon’,

LEFT(DATENAME(MM, @Datetime),3))

IF (CHARINDEX (‘MM’,@StringDate) > 0)

SET @StringDate = REPLACE(@StringDate, ‘MM’,

RIGHT(’0′+CONVERT(VARCHAR,DATEPART(MM, @Datetime)),2))

IF (CHARINDEX (‘M’,@StringDate) > 0)

SET @StringDate = REPLACE(@StringDate, ‘M’,

CONVERT(VARCHAR,DATEPART(MM, @Datetime)))

IF (CHARINDEX (‘DD’,@StringDate) > 0)

SET @StringDate = REPLACE(@StringDate, ‘DD’,

RIGHT(’0′+DATENAME(DD, @Datetime),2))

IF (CHARINDEX (‘D’,@StringDate) > 0)

SET @StringDate = REPLACE(@StringDate, ‘D’,

DATENAME(DD, @Datetime))

RETURN @StringDate

END

– Microsoft SQL Server date format function test

– MSSQL formatting dates

SELECT dbo.fnFormatDate (getdate(), ‘MM/DD/YYYY’) – 01/03/2012

SELECT dbo.fnFormatDate (getdate(), ‘DD/MM/YYYY’) – 03/01/2012

SELECT dbo.fnFormatDate (getdate(), ‘M/DD/YYYY’) – 1/03/2012

SELECT dbo.fnFormatDate (getdate(), ‘M/D/YYYY’) – 1/3/2012

SELECT dbo.fnFormatDate (getdate(), ‘M/D/YY’) – 1/3/12

SELECT dbo.fnFormatDate (getdate(), ‘MM/DD/YY’) – 01/03/12

SELECT dbo.fnFormatDate (getdate(), ‘MON DD, YYYY’) – JAN 03, 2012

SELECT dbo.fnFormatDate (getdate(), ‘Mon DD, YYYY’) – Jan 03, 2012

SELECT dbo.fnFormatDate (getdate(), ‘Month DD, YYYY’) – January 03, 2012

SELECT dbo.fnFormatDate (getdate(), ‘YYYY/MM/DD’) – 2012/01/03

SELECT dbo.fnFormatDate (getdate(), ‘YYYYMMDD’) – 20120103

SELECT dbo.fnFormatDate (getdate(), ‘YYYY-MM-DD’) – 2012-01-03

– CURRENT_TIMESTAMP returns current system date and time in standard internal format

SELECT dbo.fnFormatDate (CURRENT_TIMESTAMP,‘YY.MM.DD’) – 12.01.03

————

/***** SELECTED SQL DATE/DATETIME FORMATS WITH NAMES *****/

– SQL format datetime

– Default format: Oct 23 2006 10:40AM

SELECT [Default]=CONVERT(varchar,GETDATE(),100)

– US-Style format: 10/23/2006

SELECT [US-Style]=CONVERT(char,GETDATE(),101)

– ANSI format: 2006.10.23

SELECT [ANSI]=CONVERT(char,CURRENT_TIMESTAMP,102)

– UK-Style format: 23/10/2006

SELECT [UK-Style]=CONVERT(char,GETDATE(),103)

– German format: 23.10.2006

SELECT [German]=CONVERT(varchar,GETDATE(),104)

– ISO format: 20061023

SELECT ISO=CONVERT(varchar,GETDATE(),112)

– ISO8601 format: 2008-10-23T19:20:16.003

SELECT [ISO8601]=CONVERT(varchar,GETDATE(),126)

————

– SQL Server datetime formats

– Century date format MM/DD/YYYY usage in a query

– Format dates SQL Server 2005

SELECT TOP (1)

SalesOrderID,

OrderDate = CONVERT(char(10), OrderDate, 101),

OrderDateTime = OrderDate

FROM AdventureWorks.Sales.SalesOrderHeader

/* Result

SalesOrderID OrderDate OrderDateTime

43697 07/01/2001 2001-07-01 00:00:00.000

– SQL update datetime column

– SQL datetime DATEADD

UPDATE Production.Product

SET ModifiedDate=DATEADD(dd,1, ModifiedDate)

WHERE ProductID = 1001

– MM/DD/YY date format

– Datetime format sql

SELECT TOP (1)

SalesOrderID,

OrderDate = CONVERT(varchar(8), OrderDate, 1),

OrderDateTime = OrderDate

FROM AdventureWorks.Sales.SalesOrderHeader

ORDER BY SalesOrderID desc

/* Result

SalesOrderID OrderDate OrderDateTime

75123 07/31/04 2004-07-31 00:00:00.000

– Combining different style formats for date & time

– Datetime formats

– Datetime formats sql

DECLARE @Date DATETIME

SET @Date = ’2015-12-22 03:51 PM’

SELECT CONVERT(CHAR(10),@Date,110) + SUBSTRING(CONVERT(varchar,@Date,0),12,8)

– Result: 12-22-2015 3:51PM

– Microsoft SQL Server cast datetime to string

SELECT stringDateTime=CAST (getdate() as varchar)

– Result: Dec 29 2012 3:47AM

————

– SQL Server date and time functions overview

————

– SQL Server CURRENT_TIMESTAMP function

– SQL Server datetime functions

– local NYC – EST – Eastern Standard Time zone

– SQL DATEADD function – SQL DATEDIFF function

SELECT CURRENT_TIMESTAMP – 2012-01-05 07:02:10.577

– SQL Server DATEADD function

SELECT DATEADD(month,2,’2012-12-09′) – 2013-02-09 00:00:00.000

– SQL Server DATEDIFF function

SELECT DATEDIFF(day,’2012-12-09′,’2013-02-09′) – 62

– SQL Server DATENAME function

SELECT DATENAME(month, ’2012-12-09′) – December

SELECT DATENAME(weekday, ’2012-12-09′) – Sunday

– SQL Server DATEPART function

SELECT DATEPART(month, ’2012-12-09′) – 12

– SQL Server DAY function

SELECT DAY(’2012-12-09′) – 9

– SQL Server GETDATE function

– local NYC – EST – Eastern Standard Time zone

SELECT GETDATE() – 2012-01-05 07:02:10.577

– SQL Server GETUTCDATE function

– London – Greenwich Mean Time

SELECT GETUTCDATE() – 2012-01-05 12:02:10.577

– SQL Server MONTH function

SELECT MONTH(’2012-12-09′) – 12

– SQL Server YEAR function

SELECT YEAR(’2012-12-09′) – 2012

————

– T-SQL Date and time function application

– CURRENT_TIMESTAMP and getdate() are the same in T-SQL

————

– SQL first day of the month

– SQL first date of the month

– SQL first day of current month – 2012-01-01 00:00:00.000

SELECT DATEADD(dd,0,DATEADD(mm, DATEDIFF(mm,0,CURRENT_TIMESTAMP),0))

– SQL last day of the month

– SQL last date of the month

– SQL last day of current month – 2012-01-31 00:00:00.000

SELECT DATEADD(dd,-1,DATEADD(mm, DATEDIFF(mm,0,CURRENT_TIMESTAMP)+1,0))

– SQL first day of last month

– SQL first day of previous month – 2011-12-01 00:00:00.000

SELECT DATEADD(mm,-1,DATEADD(mm, DATEDIFF(mm,0,CURRENT_TIMESTAMP),0))

– SQL last day of last month

– SQL last day of previous month – 2011-12-31 00:00:00.000

SELECT DATEADD(dd,-1,DATEADD(mm, DATEDIFF(mm,0,DATEADD(MM,-1,GETDATE()))+1,0))

– SQL first day of next month – 2012-02-01 00:00:00.000

SELECT DATEADD(mm,1,DATEADD(mm, DATEDIFF(mm,0,CURRENT_TIMESTAMP),0))

– SQL last day of next month – 2012-02-28 00:00:00.000

SELECT DATEADD(dd,-1,DATEADD(mm, DATEDIFF(mm,0,DATEADD(MM,1,GETDATE()))+1,0))

– SQL first day of a month – 2012-10-01 00:00:00.000

DECLARE @Date datetime; SET @Date = ’2012-10-23′

SELECT DATEADD(dd,0,DATEADD(mm, DATEDIFF(mm,0,@Date),0))

– SQL last day of a month – 2012-03-31 00:00:00.000

DECLARE @Date datetime; SET @Date = ’2012-03-15′

SELECT DATEADD(dd,-1,DATEADD(mm, DATEDIFF(mm,0,@Date)+1,0))

– SQL first day of year

– SQL first day of the year - 2012-01-01 00:00:00.000

SELECT DATEADD(yy, DATEDIFF(yy,0,CURRENT_TIMESTAMP), 0)

– SQL last day of year

– SQL last day of the year – 2012-12-31 00:00:00.000

SELECT DATEADD(yy,1, DATEADD(dd, -1, DATEADD(yy,

DATEDIFF(yy,0,CURRENT_TIMESTAMP), 0)))

– SQL last day of last year

– SQL last day of previous year – 2011-12-31 00:00:00.000

SELECT DATEADD(dd,-1,DATEADD(yy,DATEDIFF(yy,0,CURRENT_TIMESTAMP), 0))

– SQL calculate age in years, months, days

– SQL table-valued function

– SQL user-defined function – UDF

– SQL Server age calculation – date difference

– Format dates SQL Server 2008

USE AdventureWorks2008;

CREATE FUNCTION fnAge (@BirthDate DATETIME)

RETURNS @Age TABLE(Years INT,

Months INT,

Days INT)

BEGIN

DECLARE @EndDate DATETIME, @Anniversary DATETIME

SET @EndDate = Getdate()

SET @Anniversary = Dateadd(yy,Datediff(yy,@BirthDate,@EndDate),@BirthDate)

INSERT @Age

SELECT Datediff(yy,@BirthDate,@EndDate) - (CASE

WHEN @Anniversary > @EndDate THEN 1

ELSE 0

END), 0, 0

UPDATE @Age SET Months = Month(@EndDate - @Anniversary) - 1

UPDATE @Age SET Days = Day(@EndDate - @Anniversary) - 1

RETURN

END

– Test table-valued UDF

SELECT * FROM fnAge(’1956-10-23′)

SELECT * FROM dbo.fnAge(’1956-10-23′)

/* Results

Years Months Days

52 4 1

———-

– SQL date range between

———-

– SQL between dates

USE AdventureWorks;

– SQL between

SELECT POs=COUNT(*) FROM Purchasing.PurchaseOrderHeader

WHERE OrderDate BETWEEN ’20040301′ AND ’20040315′

– Result: 108

– BETWEEN operator is equivalent to >=…AND….<=

SELECT POs=COUNT(*) FROM Purchasing.PurchaseOrderHeader

WHERE OrderDate

BETWEEN ’2004-03-01 00:00:00.000′ AND ’2004-03-15 00:00:00.000′

Orders with OrderDates

’2004-03-15 00:00:01.000′ – 1 second after midnight (12:00AM)

’2004-03-15 00:01:00.000′ – 1 minute after midnight

’2004-03-15 01:00:00.000′ – 1 hour after midnight

are not included in the two queries above.

– To include the entire day of 2004-03-15 use the following two solutions

SELECT POs=COUNT(*) FROM Purchasing.PurchaseOrderHeader

WHERE OrderDate >= ’20040301′ AND OrderDate < ’20040316′

– SQL between with DATE type (SQL Server 2008)

SELECT POs=COUNT(*) FROM Purchasing.PurchaseOrderHeader

WHERE CONVERT(DATE, OrderDate) BETWEEN ’20040301′ AND ’20040315′

———-

– Non-standard format conversion: 2011 December 14

– SQL datetime to string

SELECT [YYYY Month DD] =

CAST(YEAR(GETDATE()) AS VARCHAR(4))+ ‘ ‘+

DATENAME(MM, GETDATE()) + ‘ ‘ +

CAST(DAY(GETDATE()) AS VARCHAR(2))

– Converting datetime to YYYYMMDDHHMMSS format: 20121214172638

SELECT replace(convert(varchar, getdate(),111),‘/’,”) +

replace(convert(varchar, getdate(),108),‘:’,”)

– Datetime custom format conversion to YYYY_MM_DD

select CurrentDate=rtrim(year(getdate())) + ‘_’ +

right(’0′ + rtrim(month(getdate())),2) + ‘_’ +

right(’0′ + rtrim(day(getdate())),2)

– Converting seconds to HH:MM:SS format

declare @Seconds int

set @Seconds = 10000

select TimeSpan=right(’0′ +rtrim(@Seconds / 3600),2) + ‘:’ +

right(’0′ + rtrim((@Seconds % 3600) / 60),2) + ‘:’ +

right(’0′ + rtrim(@Seconds % 60),2)

– Result: 02:46:40

– Test result

select 2*3600 + 46*60 + 40

– Result: 10000

– Set the time portion of a datetime value to 00:00:00.000

– SQL strip time from date

– SQL strip time from datetime

SELECT CURRENT_TIMESTAMP ,DATEADD(dd, DATEDIFF(dd, 0, CURRENT_TIMESTAMP), 0)

– Results: 2014-01-23 05:35:52.793 2014-01-23 00:00:00.000

/*******

VALID DATE RANGES FOR DATE/DATETIME DATA TYPES

SMALLDATETIME date range:

January 1, 1900 through June 6, 2079

DATETIME date range:

January 1, 1753 through December 31, 9999

DATETIME2 date range (SQL Server 2008):

January 1,1 AD through December 31, 9999 AD

DATE date range (SQL Server 2008):

January 1, 1 AD through December 31, 9999 AD

*******/

– Selecting with CONVERT into different styles

– Note: Only Japan & ISO styles can be used in ORDER BY

SELECT TOP(1)

Italy = CONVERT(varchar, OrderDate, 105)

, USA = CONVERT(varchar, OrderDate, 110)

, Japan = CONVERT(varchar, OrderDate, 111)

, ISO = CONVERT(varchar, OrderDate, 112)

FROM AdventureWorks.Purchasing.PurchaseOrderHeader

ORDER BY PurchaseOrderID DESC

/* Results

Italy USA Japan ISO

25-07-2004 07-25-2004 2004/07/25 20040725

– SQL Server convert date to integer

DECLARE @Datetime datetime

SET @Datetime = ’2012-10-23 10:21:05.345′

SELECT DateAsInteger = CAST (CONVERT(varchar,@Datetime,112) as INT)

– Result: 20121023

– SQL Server convert integer to datetime

DECLARE @intDate int

SET @intDate = 20120315

SELECT IntegerToDatetime = CAST(CAST(@intDate as varchar) as datetime)

– Result: 2012-03-15 00:00:00.000

————

– SQL Server CONVERT script applying table INSERT/UPDATE

————

– SQL Server convert date

– Datetime column is converted into date only string column

USE tempdb;

CREATE TABLE sqlConvertDateTime (

DatetimeCol datetime,

DateCol char(8));

INSERT sqlConvertDateTime (DatetimeCol) SELECT GETDATE()

UPDATE sqlConvertDateTime

SET DateCol = CONVERT(char(10), DatetimeCol, 112)

SELECT * FROM sqlConvertDateTime

– SQL Server convert datetime

– The string date column is converted into datetime column

UPDATE sqlConvertDateTime

SET DatetimeCol = CONVERT(Datetime, DateCol, 112)

SELECT * FROM sqlConvertDateTime

– Adding a day to the converted datetime column with DATEADD

UPDATE sqlConvertDateTime

SET DatetimeCol = DATEADD(day, 1, CONVERT(Datetime, DateCol, 112))

SELECT * FROM sqlConvertDateTime

– Equivalent formulation

– SQL Server cast datetime

UPDATE sqlConvertDateTime

SET DatetimeCol = DATEADD(dd, 1, CAST(DateCol AS datetime))

SELECT * FROM sqlConvertDateTime

DROP TABLE sqlConvertDateTime

/* First results

DatetimeCol DateCol

2014-12-25 16:04:15.373 20141225 */

/* Second results:

DatetimeCol DateCol

2014-12-25 00:00:00.000 20141225 */

/* Third results:

DatetimeCol DateCol

2014-12-26 00:00:00.000 20141225 */

————

– SQL month sequence – SQL date sequence generation with table variable

– SQL Server cast string to datetime – SQL Server cast datetime to string

– SQL Server insert default values method

DECLARE @Sequence table (Sequence int identity(1,1))

DECLARE @i int; SET @i = 0

DECLARE @StartDate datetime;

SET @StartDate = CAST(CONVERT(varchar, year(getdate()))+

RIGHT(’0′+convert(varchar,month(getdate())),2) + ’01′ AS DATETIME)

WHILE ( @i < 120)

BEGIN

INSERT @Sequence DEFAULT VALUES

SET @i = @i + 1

END

SELECT MonthSequence = CAST(DATEADD(month, Sequence,@StartDate) AS varchar)

FROM @Sequence

/* Partial results:

MonthSequence

Jan 1 2012 12:00AM

Feb 1 2012 12:00AM

Mar 1 2012 12:00AM

Apr 1 2012 12:00AM

————

– SQL Server Server datetime internal storage

– SQL Server datetime formats

————

– SQL Server datetime to hex

SELECT Now=CURRENT_TIMESTAMP, HexNow=CAST(CURRENT_TIMESTAMP AS BINARY(8))

/* Results

Now HexNow

2009-01-02 17:35:59.297 0x00009B850122092D

– SQL Server date part – left 4 bytes – Days since 1900-01-01

SELECT Now=DATEADD(DAY, CONVERT(INT, 0x00009B85), ’19000101′)

– Result: 2009-01-02 00:00:00.000

– SQL time part – right 4 bytes – milliseconds since midnight

– 1000/300 is an adjustment factor

– SQL dateadd to Midnight

SELECT Now=DATEADD(MS, (1000.0/300)* CONVERT(BIGINT, 0x0122092D), ’2009-01-02′)

– Result: 2009-01-02 17:35:59.290

————

– String date and datetime date&time columns usage

– SQL Server datetime formats in tables

————

USE tempdb;

SET NOCOUNT ON;

– SQL Server select into table create

SELECT TOP (5)

FullName=convert(nvarchar(50),FirstName+‘ ‘+LastName),

BirthDate = CONVERT(char(8), BirthDate,112),

ModifiedDate = getdate()

INTO Employee

FROM AdventureWorks.HumanResources.Employee e

INNER JOIN AdventureWorks.Person.Contact c

ON c.ContactID = e.ContactID

ORDER BY EmployeeID

– SQL Server alter table

ALTER TABLE Employee ALTER COLUMN FullName nvarchar(50) NOT NULL

ALTER TABLE Employee

ADD CONSTRAINT [PK_Employee] PRIMARY KEY (FullName )

/* Results

Table definition for the Employee table

Note: BirthDate is string date (only)

CREATE TABLE dbo.Employee(

FullName nvarchar(50) NOT NULL PRIMARY KEY,

BirthDate char(8) NULL,

ModifiedDate datetime NOT NULL

)

SELECT * FROM Employee ORDER BY FullName

/* Results

FullName BirthDate ModifiedDate

Guy Gilbert 19720515 2009-01-03 10:10:19.217

Kevin Brown 19770603 2009-01-03 10:10:19.217

Rob Walters 19650123 2009-01-03 10:10:19.217

Roberto Tamburello 19641213 2009-01-03 10:10:19.217

Thierry D’Hers 19490829 2009-01-03 10:10:19.217

– SQL Server age

SELECT FullName, Age = DATEDIFF(YEAR, BirthDate, GETDATE()),

RowMaintenanceDate = CAST (ModifiedDate AS varchar)

FROM Employee ORDER BY FullName

/* Results

FullName Age RowMaintenanceDate

Guy Gilbert 37 Jan 3 2009 10:10AM

Kevin Brown 32 Jan 3 2009 10:10AM

Rob Walters 44 Jan 3 2009 10:10AM

Roberto Tamburello 45 Jan 3 2009 10:10AM

Thierry D’Hers 60 Jan 3 2009 10:10AM

– SQL Server age of Rob Walters on specific dates

– SQL Server string to datetime implicit conversion with DATEADD

SELECT AGE50DATE = DATEADD(YY, 50, ’19650123′)

– Result: 2015-01-23 00:00:00.000

– SQL Server datetime to string, Italian format for ModifiedDate

– SQL Server string to datetime implicit conversion with DATEDIFF

SELECT FullName,

AgeDEC31 = DATEDIFF(YEAR, BirthDate, ’20141231′),

AgeJAN01 = DATEDIFF(YEAR, BirthDate, ’20150101′),

AgeJAN23 = DATEDIFF(YEAR, BirthDate, ’20150123′),

AgeJAN24 = DATEDIFF(YEAR, BirthDate, ’20150124′),

ModDate = CONVERT(varchar, ModifiedDate, 105)

FROM Employee

WHERE FullName = ‘Rob Walters’

ORDER BY FullName

/* Results

Important Note: age increments on Jan 1 (not as commonly calculated)

FullName AgeDEC31 AgeJAN01 AgeJAN23 AgeJAN24 ModDate

Rob Walters 49 50 50 50 03-01-2009

————

– SQL combine integer date & time into datetime

————

– Datetime format sql

– SQL stuff

DECLARE @DateTimeAsINT TABLE ( ID int identity(1,1) primary key,

DateAsINT int,

TimeAsINT int

)

– NOTE: leading zeroes in time is for readability only!

INSERT @DateTimeAsINT (DateAsINT, TimeAsINT) VALUES (20121023, 235959)

INSERT @DateTimeAsINT (DateAsINT, TimeAsINT) VALUES (20121023, 010204)

INSERT @DateTimeAsINT (DateAsINT, TimeAsINT) VALUES (20121023, 002350)

INSERT @DateTimeAsINT (DateAsINT, TimeAsINT) VALUES (20121023, 000244)

INSERT @DateTimeAsINT (DateAsINT, TimeAsINT) VALUES (20121023, 000050)

INSERT @DateTimeAsINT (DateAsINT, TimeAsINT) VALUES (20121023, 000006)

SELECT DateAsINT, TimeAsINT,

CONVERT(datetime, CONVERT(varchar(8), DateAsINT) + ‘ ‘+

STUFF(STUFF ( RIGHT(REPLICATE(’0′, 6) + CONVERT(varchar(6), TimeAsINT), 6),

3, 0, ‘:’), 6, 0, ‘:’)) AS DateTimeValue

FROM @DateTimeAsINT

ORDER BY ID

/* Results

DateAsINT TimeAsINT DateTimeValue

20121023 235959 2012-10-23 23:59:59.000

20121023 10204 2012-10-23 01:02:04.000

20121023 2350 2012-10-23 00:23:50.000

20121023 244 2012-10-23 00:02:44.000

20121023 50 2012-10-23 00:00:50.000

20121023 6 2012-10-23 00:00:06.000

————

– SQL Server string to datetime, implicit conversion with assignment

UPDATE Employee SET ModifiedDate = ’20150123′

WHERE FullName = ‘Rob Walters’

SELECT ModifiedDate FROM Employee WHERE FullName = ‘Rob Walters’

– Result: 2015-01-23 00:00:00.000

/* SQL string date, assemble string date from datetime parts */

– SQL Server cast string to datetime – sql convert string date

– SQL Server number to varchar conversion

– SQL Server leading zeroes for month and day

– SQL Server right string function

UPDATE Employee SET BirthDate =

CONVERT(char(4),YEAR(CAST(’1965-01-23′ as DATETIME)))+

RIGHT(’0′+CONVERT(varchar,MONTH(CAST(’1965-01-23′ as DATETIME))),2)+

RIGHT(’0′+CONVERT(varchar,DAY(CAST(’1965-01-23′ as DATETIME))),2)

WHERE FullName = ‘Rob Walters’

SELECT BirthDate FROM Employee WHERE FullName = ‘Rob Walters’

– Result: 19650123

– Perform cleanup action

DROP TABLE Employee

– SQL nocount

SET NOCOUNT OFF;

————

– sql isdate function

————

USE tempdb;

– sql newid – random sort

SELECT top(3) SalesOrderID,

stringOrderDate = CAST (OrderDate AS varchar)

INTO DateValidation

FROM AdventureWorks.Sales.SalesOrderHeader

ORDER BY NEWID()

SELECT * FROM DateValidation

/* Results

SalesOrderID stringOrderDate

56720 Oct 26 2003 12:00AM

73737 Jun 25 2004 12:00AM

70573 May 14 2004 12:00AM

– SQL update with top

UPDATE TOP(1) DateValidation

SET stringOrderDate = ‘Apb 29 2004 12:00AM’

– SQL string to datetime fails without validation

SELECT SalesOrderID, OrderDate = CAST (stringOrderDate as datetime)

FROM DateValidation

/* Msg 242, Level 16, State 3, Line 1

The conversion of a varchar data type to a datetime data type resulted in an

out-of-range value.

– sql isdate – filter for valid dates

SELECT SalesOrderID, OrderDate = CAST (stringOrderDate as datetime)

FROM DateValidation

WHERE ISDATE(stringOrderDate) = 1

/* Results

SalesOrderID OrderDate

73737 2004-06-25 00:00:00.000

70573 2004-05-14 00:00:00.000

– SQL drop table

DROP TABLE DateValidation

————

– SELECT between two specified dates – assumption TIME part is 00:00:00.000

————

– SQL datetime between

– SQL select between two dates

SELECT EmployeeID, RateChangeDate

FROM AdventureWorks.HumanResources.EmployeePayHistory

WHERE RateChangeDate >= ’1997-11-01′ AND

RateChangeDate < DATEADD(dd,1,’1998-01-05′)

/* Results

EmployeeID RateChangeDate

3 1997-12-12 00:00:00.000

4 1998-01-05 00:00:00.000

/* Equivalent to

– SQL datetime range

SELECT EmployeeID, RateChangeDate

FROM AdventureWorks.HumanResources.EmployeePayHistory

WHERE RateChangeDate >= ’1997-11-01 00:00:00′ AND

RateChangeDate < ’1998-01-06 00:00:00′

————

– SQL datetime language setting

– SQL Nondeterministic function usage – result varies with language settings

SET LANGUAGE ‘us_english’; –– Jan 12 2015 12:00AM

SELECT US = convert(VARCHAR,convert(DATETIME,’01/12/2015′));

SET LANGUAGE ‘British’; –– Dec 1 2015 12:00AM

SELECT UK = convert(VARCHAR,convert(DATETIME,’01/12/2015′));

SET LANGUAGE ‘German’; –– Dez 1 2015 12:00AM

SET LANGUAGE ‘Deutsch’; –– Dez 1 2015 12:00AM

SELECT Germany = convert(VARCHAR,convert(DATETIME,’01/12/2015′));

SET LANGUAGE ‘French’; –– déc 1 2015 12:00AM

SELECT France = convert(VARCHAR,convert(DATETIME,’01/12/2015′));

SET LANGUAGE ‘Spanish’; –– Dic 1 2015 12:00AM

SELECT Spain = convert(VARCHAR,convert(DATETIME,’01/12/2015′));

SET LANGUAGE ‘Hungarian’; –– jan 12 2015 12:00AM

SELECT Hungary = convert(VARCHAR,convert(DATETIME,’01/12/2015′));

SET LANGUAGE ‘us_english’;

————

– Function for Monday dates calculation

————

USE AdventureWorks2008;

– SQL user-defined function

– SQL scalar function – UDF

CREATE FUNCTION fnMondayDate

(@Year INT,

@Month INT,

@MondayOrdinal INT)

RETURNS DATETIME

BEGIN

DECLARE @FirstDayOfMonth CHAR(10),

@SeedDate CHAR(10)

SET @FirstDayOfMonth = convert(VARCHAR,@Year) + ‘-’ + convert(VARCHAR,@Month) + ‘-01′

SET @SeedDate = ’1900-01-01′

RETURN DATEADD(DD,DATEDIFF(DD,@SeedDate,DATEADD(DD,(@MondayOrdinal * 7) - 1,

@FirstDayOfMonth)) / 7 * 7, @SeedDate)

END

– Test Datetime UDF

– Third Monday in Feb, 2015

SELECT dbo.fnMondayDate(2016,2,3)

– 2015-02-16 00:00:00.000

– First Monday of current month

SELECT dbo.fnMondayDate(Year(getdate()),Month(getdate()),1)

– 2009-02-02 00:00:00.000

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