First Create a table with the name Document in database which
requires to saving and retrieving from database.
For Save, Just am saving NameOftheDocument,Document,DocumentType
and Filename.
For that Design textbox and fileupload control and one Save button
using asp.net
Then in Save button click
event write the following code:
protected void
btnSave_Click(object sender, EventArgs e)
{
string NameOftheDocument
= txtNameOfDocument.Text;
byte[]
imgbyte = new byte[0];
string
DocType = string.Empty;
string
FileName = string.Empty;
if
(AsyFUCreateDocument.HasFile)
{
int
length = AsyFUCreateDocument.PostedFile.ContentLength;
imgbyte = new byte[length];
HttpPostedFile
img = AsyFUCreateDocument.PostedFile;
img.InputStream.Read(imgbyte,
0, length);
DocType = AsyFUCreateDocument.PostedFile.ContentType;
FileName =
AsyFUCreateDocument.PostedFile.FileName;
}
//Pass these fields are as
parameters to database and Save it.
// Create SQL Connection
SqlConnection con = new SqlConnection("data Source=ADMIN;initial catalog=databasename; user
id=Sa; password=123");
// Create SQL Command
SqlCommand cmd = new SqlCommand();
cmd.CommandText = "INSERT
INTO Document(NameOftheDocument,Document,DocumentType
, Filename)" + " VALUES (@NameOftheDocument,@Document,@DocumentType ,@ Filename)";
cmd.CommandType = CommandType.Text;
cmd.Connection = con;
SqlParameter NameOftheDocument = new SqlParameter("@NameOftheDocument",SqlDbType.VarChar,
50);
NameOftheDocument.Value = NameOftheDocument.ToString();
cmd.Parameters.Add(NameOftheDocument);
SqlParameter Document = new SqlParameter("@Document ",SqlDbType.Image,
imgbyte.Length);
Document.Value
= imgbyte;
cmd.Parameters.Add(Document);
SqlParameter DocumentType = new SqlParameter("@DocumentType
",SqlDbType.VarChar,
50);
DocumentType.Value = DocumentType.ToString();
cmd.Parameters.Add(DocumentType);
SqlParameter Filename = new SqlParameter("@Filename ",SqlDbType.VarChar,
50);
Filename.Value
= Filename.ToString();
cmd.Parameters.Add(Filename);
con.Open();
int result = cmd.ExecuteNonQuery();
con.Close();
if (result > 0)
lbmsg.Text = "Document
Uploaded";
Then retrieve data from
document table by using data Adapter and fill it into dataset.
After that:
The following article is showing about
download a document file form dataset table[0] means one datatable.
For that first you have to retrieve
data from database and Fill it into One Datatable.
Then write the following methods where
ever you requires.
public string GetMimeTypeByFileName(string
sFileName)
{
string
sMime = "application/octet-stream";
string
sExtension = System.IO.Path.GetExtension(sFileName);
if (!string.IsNullOrEmpty(sExtension))
{
sExtension = sExtension.Replace(".", "");
sExtension = sExtension.ToLower();
if
(sExtension == "xls" || sExtension
== "xlsx")
{
sMime = "application/ms-excel";
}
else
if (sExtension == "doc"
|| sExtension == "docx")
{
sMime = "application/msword";
}
else
if (sExtension == "ppt"
|| sExtension == "pptx")
{
sMime = "application/ms-powerpoint";
}
else
if (sExtension == "pdf")
{
sMime = "application/pdf";
}
else
if (sExtension == "rtf")
{
sMime = "application/rtf";
}
else
if (sExtension == "zip")
{
sMime = "application/zip";
}
else
if (sExtension == "mp3")
{
sMime = "audio/mpeg";
}
else
if (sExtension == "bmp")
{
sMime = "image/bmp";
}
else
if (sExtension == "gif")
{
sMime = "image/gif";
}
else
if (sExtension == "jpg"
|| sExtension == "jpeg")
{
sMime = "image/jpeg";
}
else
if (sExtension == "png")
{
sMime = "image/png";
}
else
if (sExtension == "tiff"
|| sExtension == "tif")
{
sMime = "image/tiff";
}
else
if (sExtension == "txt")
{
sMime = "text/plain";
}
}
return
sMime;
}
The following DataTable
dt, you can take from your dataset tables[0] then write the method and
Call the following method in Download
button click:
public void
download(DataTable dt)
{
Byte[]
bytes = (Byte[])dt.Rows[0]["Image"];
string
filename = dt.Rows[0]["FileName"].ToString();
HttpContext.Current.Response.Clear();
HttpContext.Current.Response.Buffer =
false;
HttpContext.Current.Response.Charset
= "";
HttpContext.Current.Response.Cache.SetCacheability(HttpCacheability.NoCache);
HttpContext.Current.Response.ContentType
= GetMimeTypeByFileName(filename);
HttpContext.Current.Response.AddHeader("content-disposition", "attachment;filename="+filename.Replace(" ", "_"));
HttpContext.Current.Response.BinaryWrite(bytes);
HttpContext.Current.Response.Flush();
HttpContext.Current.Response.End();
}
After clicking Download button then
you will get Open with file and Save file Options.
cool
ReplyDeletethanks for sharing this code vary useful http://soft-engineering.blogspot.in/